Anyone have a Win 2003 box they can test this on?

On Tue, 22 Mar 2005 23:05:51 +0100, azurIt <azurit (at) pobox (dot) sk [email concealed]> wrote:
>
>
> > On Tue, Mar 22, 2005 at 12:21:18PM -0000, liquid (at) cyberspace (dot) org [email concealed]
> wrote:
> > > Start Python and type (of course x.x.x.x should be replaced with
> > > IP address):
> > >
> > > import socket
> > > s=socket.socket(socket.AF_INET,socket.SOCK_RAW,4)
> > > s.sendto("",("x.x.x.x",0))
> > >
> > > Press ENTER and your win box should crash immediately.
> >
> > I tested this on WinXP SP2 with Python 2.4. The result is an
> > exception:
> >
> > socket.error: (10022, 'Invalid argument')
> >
> > I don't have Python 2.3 installed otherwise I would test that too.
> >
> > Neil
> >
>
> i got the same exception, WinXP SP2, Python 2.3.4 .
>
> azurIt
>
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